(lw - lwy)
lw
(lw minus lwy over lw.)
2006-11-30 00:35:38 · 11 answers · asked by me 1 in Science & Mathematics ➔ Mathematics
The question must be simplified, sorry. ;:) lol
2006-11-30 02:08:41 · update #1
If l,w and y are separate variables then
(lw - lwy)/lw=lw/lw - lwy/lwy = 1 - y
If lw and lwy are each a vaiable then
(lw - lwy)/lw= lw/lw - lwy/lw = 1-lwy/lw
If lw and y are variables then
(lw - lwy)/lw = lw/lw - lwy/lw = 1 -y
2006-11-30 01:04:33 · answer #1 · answered by albert 5 · 0⤊ 0⤋
Well, the only thing you can do is simplify the equation:
So, first you have to factorize the numerator:
lw(1 - y) / lw
since, there is an lw on the numerator and lw in the denominator, you can cancel these out.
Which leaves, 1-y as your answer
2006-11-30 08:38:08 · answer #2 · answered by thugster17 2 · 0⤊ 0⤋
lw gets cancelled when divided by lw.
Answer = -lwy
2006-11-30 09:14:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You can start by pulling out the lw in (lw - lwy)
So you will have:
lw(1-y)
----------
lw
Now, the lw on the top and bottom will cancel out
1-y is the answer
2006-11-30 08:56:19 · answer #4 · answered by Krisie 2 · 0⤊ 0⤋
Divide both of the first terms by (lw) and get (1-y) with the exception that l can not be zero AND w can NOT be zero because division by zero is IMPOSSIBLE!. The exception is important here... Have a great day!
2006-11-30 09:22:00 · answer #5 · answered by Eds 7 · 0⤊ 0⤋
if u are required to simplify then
lw(1-y)/lw=1-y
2006-11-30 08:39:57 · answer #6 · answered by mmmmmmmmm 1 · 0⤊ 0⤋
(lw - lwy) / (lw) = lw / lw *(1-y) = 1-y
2006-11-30 08:37:21 · answer #7 · answered by James Chan 4 · 0⤊ 0⤋
lw(1-y)/lw=1-y
2006-11-30 08:43:43 · answer #8 · answered by skull 3 · 0⤊ 0⤋
(lw - lwy) / (lw)
= (lw / lw )- (lwy/lw)
= 1-y
2006-11-30 08:42:10 · answer #9 · answered by Elsen 2 · 0⤊ 0⤋
what is the question exactly? are you solving for one of the letters? can you give some more info?
2006-11-30 08:37:45 · answer #10 · answered by Anonymous · 0⤊ 0⤋