Let x and y be two vectors
x.y is the scalar product which is defined as-
x.y=|x| |y| sin Z
| | is the magnitude
Z is the angle between the two.
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a.b=a.c
=>|a| |b| sin m =|a| |c| sin n
m :angle between a and b vectors
n :angle between a and c vectors
So we get,by dividing both sides by |a|,
|b| sin m =|c| sin n
Unless m=n,u cannot say that |b|=|c|
If m=n, |b|=|c|
Also ,b and c make same angle(m=n) with vector a
So,
vector b =vector c
In general, a.b=a.c does not mean b=c
as we cannot directly cancel a without taking the scalar product of which a is a part
2006-11-29 22:47:03
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answer #1
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answered by amudwar 3
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Consider the vectors 5 and 1 inclined at angle 15 degree and vectors 5 and 2 at angle 61.1 degree.
a.b = ab cos15 = 4.83
a.c = ac cos 61.1 =4.83
But b is not equal to c.
2006-11-29 23:02:52
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answer #2
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answered by Pearlsawme 7
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b and c has to be the same in order for this equation to be true.
a.b = a.c
example:
a = 4
b = 5
c = 5
a.5 = a.5
4.5 = 4.5
4+4+4+4+4 = 4+4+4+4+4
20 = 20
2006-11-29 23:45:01
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answer #3
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answered by Rey Arson II 3
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split the vector into the two components
x: a = a
y: b = c
don't know what exactly you need to know!
but there is no explaining necessary
2006-11-29 22:36:31
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answer #4
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answered by doctor who 2
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You have a equality. You can simplify dividing the two sides by same factor.
if you divide by a , you obtain b=c
2006-11-29 22:43:56
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answer #5
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answered by maussy 7
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If a=0
b=c is not necessary
2006-11-29 22:38:50
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answer #6
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answered by Sabakuno Gaara 1
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