Give the roots of the equation 5^2x -265^x +25 = 0?

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2006-11-29 21:46:24 · 5 answers · asked by jim s 1 in Science & Mathematics ➔ Mathematics

No. Do your own f*cking homework.

2006-11-29 21:53:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋

let 5^x=t
the equation is
t^2-26t+25=0
(t-25)(t-1)=0
t=25 that is 5^x=25
5^x=5^2 x=2
t=1 5^x=1
5^x=5^0 or x=0
so the solutions are x=0 or 2

2006-11-30 06:02:18 · answer #2 · answered by raj 7 · 1⤊ 0⤋

assuming that it is 5^(2x) -265^x +25 = 0, I get about 0.62355. but I just plotted it and looked where it crossed zero.

2006-11-30 06:38:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋

convert to a quadratic with a substitution as done above

2006-11-30 07:04:54 · answer #4 · answered by yasiru89 6 · 0⤊ 0⤋

thnx 4 the 2 points....:)
im poor on maths!!

2006-11-30 05:54:32 · answer #5 · answered by nevidsee h 1 · 0⤊ 1⤋