2006-11-29 20:23:00 · 5 answers · asked by Kia Saam K 1 in Science & Mathematics ➔ Mathematics
Hendecagon
Sum of internal angles = ([number of sides] - 2) * 180
so 11-2 = 9
9 * 180 = 1620 degrees
2006-11-29 20:36:04 · answer #1 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
The Name(s) of an 11 Sided Polygon:
"Polygons with more than 10 sides are not usually given special names. A polygon with 11 sides is described as an 11-gon, a polygon with 12 sides as a 12-gon, and so on."
http://www.learner.org/channel/courses/learningmath/geometry/session3/part_a/index.html
AND
"In geometry, a hendecagon is an 11-sided polygon. Undecagon is incorrect — the prefix is properly Greek, not Latin. A regular hendecagon has internal angles of 147.272727... degrees.
A regular hendecagon is not constructible with compass and straightedge.
The Canadian dollar coin, the Loonie, is a hendecagon. The interior design of the (US coin) Susan B. Anthony silver dollar is also a hendecagon. The Indian two-rupee coin is also a hendecagon."
http://en.wikipedia.org/wiki/Hendecagon
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Interior Angle Sum Theorem:
"If a convex polygon has n sides and S is the sum of the measures of its interior angles, then S = 180(n -2)"
http://www.mpa.candler.nc.us/student%20life/Geometry/Chp10-1.htm
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GIVEN: An 11-gon
FIND: The sum of its internal angles.
FORMULA: S = 180(n-2)
Let S = the sum of the regular polygon's internal angles,
measured in degrees
Let n = the number of sides in the regular polygon.
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SOLUTION:
S = 180(n-2)
S = 180[ (11) - 2 ]
S = 180[ 1(11) - 2 ]
S = 180(11 - 2)
S = 180(9)
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ANSWER:
S = 1,620 degrees is the sum of the internal angles of Hendecagon.
(also known as an 11-gon)
2006-11-30 05:23:07 · answer #2 · answered by LovesMath 3 · 0⤊ 0⤋
hendecagon
divide this by triangles from only one corner
11-2 =9 triangular
9*180= 1620
2006-11-30 04:43:22 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
Tetra-hedron?
360 degrees?
2006-11-30 04:27:21 · answer #4 · answered by Feeling new @ 42 4 · 0⤊ 0⤋
HENDECAGON, 9*180 = 1620 DEGREES
2006-11-30 05:14:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋