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2006-11-29 20:08:43 · 3 answers · asked by Lalith B 1 in Science & Mathematics Mathematics

3 answers

The solution to this can't be found using elementary functions. That is, you won't find a solution consisting of the functions we know (sin, cos, tan, ln, e^, a^, sqrt). Integration with the basic methods would be futile.

The actual solution consists of some variation of the error function erf(x).

2006-11-29 20:39:38 · answer #1 · answered by Puggy 7 · 2 0

Use integration by parts.

u = x^2 du = 2xdx
v = e^u dv = e^udu

uv - Int[ vdu]

2006-11-29 20:27:14 · answer #2 · answered by Anonymous · 0 3

[e^(x^2)]/(2x) + c

2006-11-29 20:36:49 · answer #3 · answered by iyiogrenci 6 · 0 2

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