A "formula" that has me stumped, please help........?

Question

I don't really know how to type this in, but here it goes:
solve the following for W:
c=w squared times L squared, over 24t squared.... Please help

Answer 1

C = (W^2*L^2) / (24T^2)
C(24T^2) = W^2*L^2
[C(24T^2)]/L^2 = W^2
Answer:
W = sq.rt {[C(24T^2)]/L^2}

Answer 2

Well, the information you gave is:
c = (w^2 x L^2) / 24t^2

So, as the question just ask me to solve the following for W but I do not have the required information, I could only assume that I am supposed to express w in terms of c, L and t.

c = (w^2 x L^2) / 24t^2
c x 24t^2 = w^2 x L^2
(c x 24t^2) / L^2 = w^2
w = square root [(c x 24t^2) / L^2]

Answer 3

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Answer 4

c = w^2 * L^2 / (24t^2)

Multiply both sides by 24t^2 :

24ct^2 = w^2 * L^2

Divide both sides by L^2 :

24ct^2 / L^2 = w^2

Take the square root of both sides,
noting that √(24) = √(2^2 * 6) = 2√(6)

w = (2t / L) * √(6c)

Answer 5

SOLVE: for "w"
GIVEN: c=(w^2 times L^2) / 24t^2


SOLUTION:

c=(w^2 times L^2) / (24t^2)

(24t^2) times (c) = (24t^2) times { [ (w^2) times (L^2) ] / (24t^2) }

24ct^2 = (w^2) times (L^2)

(24ct^2) / (L^2) = [ (w^2) times (L^2) ] / (L^2)

(24ct^2) / (L^2) = w^2

square root [ (24ct^2) / (L^2) ] = square root ( w^2 )

square root (24ct^2) / square root (L^2) = w

square root [ (4t^2)(6c) ] / L = w

[ square root (4t^2) ] times [square root (6c) ] / L = w



ANSWER:
2t times the square root of 6c all over L = w

Answer 6

w = T times the square root of 24c all over L

Answer 7

Actually the asker hasn't asked us to do anything with it. Help you how? Make a song about it?

Okay, now that you editted in 'solve for W' that helps.

Answer 8

c=w^2l^2/24t^2

Answer 9

dude, u gave 4 variables in a "formula" and u wan to solve one of them????

we need more info man

Edit: he did say to solve for W

Answer 10

C² = W²L² / 24T²

24T²C = W²L²

24T²C/L² = W²L² / L²

24T²C / L² = W²

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