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Hydrazine hydrate(50% as N2H4 solution) chloride less than 0.1% as Nacl,
Whether the offer CL- 8.5 mg/kg is fulfilling the specs mentioned above??
what is realtion between CL- 8.5 mg/kg and chloride less than 0.1% as Nacl,
Please expalin...
Many thanks in advance!!!

2006-11-29 19:28:52 · 1 answers · asked by samuel_sonu 1 in Science & Mathematics Chemistry

1 answers

First of all 0.1% NaCl corresponds to 0.1 gr of NaCl in 100 ml solution.(unless it is mentioned that it is 0.1% (w/w) which would then be 0.1 g NaCl in 100 g solution)
Since you have 35.5 g Cl- for every 58.5 g NaCl, 0.1 g NaCl correspond to 0.1*(35.5/58.5) = 0.060684 g =60.68 mg Cl-

The density of hydrazine hydrate is d=1.027 g/ml So the 100 ml are m=d*V=1.027*100= 102.7 g

So you have 60.68 mg/102.7 g = 591*10^-3 mg/g =591 mg/kg

Therefore the specification Cl- less than 0.1% as NaCl is equivalent to less than 591 mg Cl-/kg

So 8.5 mg Cl-/kg solution meets the requirements

2006-11-29 22:00:23 · answer #1 · answered by bellerophon 6 · 0 0

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