2006-11-29 19:16:10 · 6 answers · asked by DEBRA S 1 in Science & Mathematics ➔ Mathematics
log a (x)= 3.58 and log a (y)= 4.79,
loga(y/x)=loga(y)-loga(x)
loga(y/x)=4.79-3.58
loga(y/x)=1.21
2006-11-29 19:29:25 · answer #1 · answered by gaufire 1 · 0⤊ 0⤋
GIVEN:
LOG a (x) = 3.58
LOG a (y) = 4.79
FIND:
LOG a (y/x)
SOLUTION:
LOG a (y/x)
REMEMBER: The LOG of two numbers being divided,
Is the DIFFERENCE of two LOGswith the same base of the original LOG. (Two #'s Divided = Subtraction of Two LOGs
[ LOG a (y) ] - [ LOG a (x) ]
[4.79] - [3.58]
1[4.79] -1[3.58]
4.79 - 3.58
1.21
ANSWER:
1.21
2006-11-30 04:16:53 · answer #2 · answered by LovesMath 3 · 0⤊ 0⤋
we have: log a (y/x)=log a y- log a x (condition: log a y and log a x must be more than 0 tto make log a (y/x) meaningful)
log a (y/x)=log a y- log a x
log a (x)=3.58 and log a (y)=4.79
so log a (y/x)=4.79-3.58=1.21
conclusion:log a (y/x)=1.21
2006-11-30 08:18:58 · answer #3 · answered by Huynh Dinh Tri 2 · 0⤊ 0⤋
log a (x)= 3.58 and log a (y)= 4.79,
loga(y/x)=loga(y)-loga(x)
loga(y/x)=4.79-3.58
loga(y/x)=1.21
2006-11-30 03:21:40 · answer #4 · answered by riya s 2 · 0⤊ 0⤋
log(y/x)=logy-logx
=4.79-3.58
=1.21
2006-11-30 03:25:26 · answer #5 · answered by raj 7 · 0⤊ 0⤋
log_a (y/x)
=log_a(y) - log_a (x)
= 4.79-3.58
=1. 21
2006-11-30 03:19:35 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋