Percent Yield?

0 ⤊

I forgot how to calculate this...

For the balanced equation shown below, if the reaction of 79.3 grams of C2H4F2 produces 18.0 grams of HF, what is the percent yield?

2C2H4F2 + 5O2 ---> 4CO2 + 2H2O + 4HF

2006-11-29 18:33:14 · 2 answers · asked by Megan T 1 in Science & Mathematics ➔ Chemistry

2 answers

the moles of C2H4F2 79.3 / 66 = 1.2
the moles of HF produced with the percent yield 100% 1.2*4/2 = 2.4
the grams of HF produced with the percent yield 100% 2.4 * 20 = 48g
the percent yield : 18/48 *100 = 37.5%

2006-11-29 18:46:57 · answer #1 · answered by James Chan 4 · 0⤊ 0⤋

use:

www.wikipedia.org

2006-11-29 18:48:02 · answer #2 · answered by noga_4ever _ 1 · 0⤊ 1⤋