2006-11-29 18:09:10 · 6 answers · asked by DEBRA S 1 in Science & Mathematics ➔ Mathematics
ln[(x+50)/3]=ln(x-3)
(x+50)/3=x-3
x/3+50/3=x-9/3
59/3=(2/3)x
59=2x
x = 59/2
2006-11-29 18:11:17 · answer #1 · answered by jacinablackbox 4 · 1⤊ 0⤋
In(x+50)-In(3)=In(x-3) : x must be greater than 3
<=>In(x+50)=In[3(x-3)]
<=> x+50 = 3(x-3)
<=> x = 59/2
2006-11-29 18:14:07 · answer #2 · answered by James Chan 4 · 0⤊ 0⤋
Log laws tell us the left side is equal to
ln((x+50)/3), so you just have to solve
(x+50)/3 = x-3 You know the rest?
x+50 = 3x-9 etc.
2006-11-29 18:12:26 · answer #3 · answered by Hy 7 · 0⤊ 0⤋
In(x+50)-In(3)=In(x-3)?
ln(x+50/3)=ln(x-3)
x+50=3x-9
so
50+9=3x-x
59=2x
x=29.5
2006-11-29 19:41:13 · answer #4 · answered by riya s 2 · 0⤊ 0⤋
In(x+50)-In(3)=In(x-3)
In[(x + 50) / (3)] = ln(x - 3)
by comparison
(x + 50) / (3) = (x - 3)
x + 50 = 3x - 9
2x = 59
x = 59/2
x = 29.5
2006-11-29 18:17:35 · answer #5 · answered by csp 2 · 0⤊ 0⤋
ln(x/3+50/3)=ln(x-3)
removing log ,we would get ,
x/3+50/3=x-3
59/3=2x/3
x=29.5
2006-11-29 19:15:04 · answer #6 · answered by jedi Knight 2 · 0⤊ 0⤋