A bob of mass m is suspended from a string of length, L, forming a pendulum. The period of this pendulum is 2.0s. If the pendulum bob is replaced with one of mass (1/3)m and the length of the pendulum is increased to 2L , what is the period of oscillation?
2006-11-29 17:53:11 · 3 answers · asked by peri2216 1 in Science & Mathematics ➔ Physics
http://en.wikipedia.org/wiki/Pendulum
2006-11-29 18:07:43 · answer #1 · answered by gp4rts 7 · 0⤊ 1⤋
The differential equation to describe oscillation of a pendulum of length l is
This is a nonlinear equation. For small oscillation amplitude,
it can be linearized as
The oscillation frequency is thus given by
As the amplitude increases, the oscillation frequency becomes smaller. The frequency corrected for a finite amplitude is approximately given by
Try in this form!!!
2006-11-29 18:01:29 · answer #2 · answered by king 3 · 0⤊ 0⤋
in case you time 10 swings, then divide the time by 10 the timing blunders for each swing is seriously decreased (decreased by about 9/10 surely). So the reason you do it really is for timing accuracy. i wager you attempt to calculate acceleration via gravity - the pendulum is between the further classic techniques.
2016-11-29 23:16:40 · answer #3 · answered by erke 4 · 0⤊ 0⤋