2006-11-29 17:22:11 · 6 answers · asked by linh n 1 in Science & Mathematics ➔ Mathematics
x^2 - x + some unknown value C
2x^n+1 / n+1 is the rule in this case. If you have a point, you can then plug it into the resulting equation to figure out "C"
2006-11-29 17:28:34 · answer #1 · answered by On a Mission 3 · 0⤊ 0⤋
antiderivative of the function 2x-1 mean integrate of the function 2x-1.
the answer is x^2 - x + c
2006-11-29 17:29:53 · answer #2 · answered by csp 2 · 0⤊ 0⤋
you can split it up into two different antiderivatives:
2x and -1, the antiderivative of 2x is x^2 and the antiderivative of -1 is -x, so you have x^2 -x and you add a constant, C:
x^2-x+C
2006-11-29 17:27:06 · answer #3 · answered by nemahknatut88 2 · 0⤊ 0⤋
x^2 - x + C
2006-11-29 17:23:47 · answer #4 · answered by MikeC 3 · 0⤊ 0⤋
antiderivative or integral of 2x-1 is log(2x-1)
2006-11-29 17:26:58 · answer #5 · answered by shruti 1 · 0⤊ 1⤋
x^2 - x + const
2006-11-29 17:24:15 · answer #6 · answered by warren_d_smith31 3 · 0⤊ 0⤋