320=(0.4+2x)^2/(0.05-x)(0.04-x)
please show me the steps
2006-11-29 16:27:12 · 6 answers · asked by tanny 1 in Science & Mathematics ➔ Mathematics
320 = (0.4 + 2x)^2 / [(0.05 - x)(0.04 - x)]
Multiply both sides by (0.05 - x)(0.04 - x).
320(0.05 - x)(0.04 - x) = (0.4 + 2x)^2
Multiply out both sides and sum like terms.
0.64 - 28.8x + 320x^2 = 0.16 + 1.6x + 4x^2
Subtract RHS from both sides.
316x^2 - 30.4x + 0.48 = 0
Multiply both sides by 100 to rid decimals.
31600x^2 - 3040x + 48 = 0
Divide by 16 which is the common factor.
1975x^2 - 190x + 3 = 0
This is now the quadratic in its final form.
To find the 2 values for x, use the quadratic formula.
x = {190 ± √ [190^2 - 4(1975)(3) ]} / (2*1975)
Thus, x = 0.01991005 or 0.07629248
2006-11-29 23:48:20 · answer #1 · answered by falzoon 7 · 0⤊ 0⤋
You need to repost the question with more spaces.
All we see is 320=(0.4+2x)^2/(0.05-x)(0.04-x...
2006-11-30 00:44:27 · answer #2 · answered by Michael M 6 · 0⤊ 0⤋
i really can't understand the solution that was given by GOPAL. GOPAL can yu plz explain it more detail....... thanx
2006-11-30 00:53:23 · answer #3 · answered by csp 2 · 0⤊ 0⤋
No idea
2006-11-30 00:38:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋
320=0.14+4x^2/(0.002+x^2-0.09x)
0.640+320x^2-28.8x=0.14+4x^2
316x^2-28.8x+0.5=0
=>3160x^2-288x+5=0
2006-11-30 00:46:56 · answer #5 · answered by raj 7 · 0⤊ 0⤋
pay attention in class...............lmao i crack me up
2006-11-30 00:29:43 · answer #6 · answered by Im Just Blessed 2 · 0⤊ 2⤋