2006-11-29 15:55:27 · 2 answers · asked by Khazz S 2 in Science & Mathematics ➔ Mathematics
It depends on whether you want the mean number of heads, the total number of heads, etc.
If you want the total, multiply the standard deviation by sqrt(n), where you have n tosses.
If you want the average, divide by sqrt(n).
(Note, the formula talked about below is for the *margin* of error, not the standard error. And thats only for means.)
2006-11-29 16:01:08 · answer #1 · answered by stephen m 4 · 0⤊ 0⤋
Isn't the standard error
Z*sigma/sqrt(n) ? Where Z is the critical value related to your confidence interval. For a 2-sided test with a confidence interval of 95%, then you distribute the 5% in the two tails. Then the Z for the error equation about is 1.96 (that's the P= 0.975 from the table.
2006-11-29 16:08:45 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋