How do you find Final velocity in this question:?

Question

Mass is .421 kilograms
Height is .041 m
total distance is .1102 m
Vi- 0 m/s
Angle- 15 degrees
Time- 1.29 seconds
Gravity- 9.81 m/s^2 (meters per second squared)
Show formulas please.

All i'm looking for is the velocity after the mass slides down the frictionless inclined plane. Of course there are the forces acting on it, i just need to know how to find it. Hope that helps.

Answer 1

formula

v^2 = u^2 + 2gh

v = final velocity
u = initial velocity

so v^2 = 0 + 2*9.81*0.041 = 0.80442 meter

thus v = 0.8968 meter / second

here mass and angle is not required.. unless some conditions are given ... which is none here ... so 0.8968 meter/second is the answer

Answer 2

the best thing about energy is that it is conserveed and it has no direction.

at the top while in restless position hte mechanical energy equals its potential energy.
and the mechanical energy at the bottom equals is kinetic energy

thus,

m*g*h = 1/2m *u^2.


the m is cancelled out therefore we get to the point where u at the bottom is

uf= Sqrt(2*g*h) = 0.8968 m/sec. this is the easy way




the difficult way goes like that.



sin(x) = 0.041 / 0.1102 => (x) = 21.84 degrees.

take the vector of the weight in the direction of velocity. you know the angles therefore the force -=> acceleration analysis.....too much algebra and then the velocity becomes known.

Answer 3

Energy, it' all about energy.

Before the drop, there's only potential energy:

mass x g x h

At the impact there's only kinetic energy:

I'd say on the basis of the angle, the problem is impossible and don't even do the work.

mass x velocity squared.

the rest is algebra.

angle and time are irrelevant.

In fact, the 15 degree angle to the gravatational field is impossible if the initial velocity is zero.

I'd just say the problem is impossible because of the given angle and don't even bother to do the work.