Given the following rational function:
f(x)= 2x^3+3x^2-2 / x^2-4
Find the equations for the horizontal or oblique asymptotes.
thanks!
2006-11-29 14:40:40 · 3 answers · asked by love_never_wanted_me 1 in Science & Mathematics ➔ Mathematics
please, all i need is horzitonal asymptotes.. please please.. i dont' know how to do it..
2006-11-29 14:49:45 · update #1
Never mind; I had a mistaken idea about what an oblique asymptote is. :(
2006-11-29 14:52:00 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
f(x)= 2x^3+3x^2-2 / x^2-4
2x^3+3x^2-2 = (x^2 - 4)(2x + 3) + 8x + 10
f(x) = 2x + 3 + (8x + 10) / (x^2 - 4)
oblique asymptotes: y = 2x + 3
It have no horizontal asymptotes.
vertical asymptotes: x = 2 , x = -2
2006-11-29 14:46:33 · answer #2 · answered by can_t_get_enough 2 · 3⤊ 0⤋
could u pleease explain
it is (-2/x^2)-4 or (-2/(x^2-4))
thanks
2006-11-29 14:45:34 · answer #3 · answered by sidharth 2 · 0⤊ 0⤋