There is only one step. Take the quadratic formula and plug in the numbers.
If ax^2 + bx + c = 0,
x = (-b +/- sqrt(b^2-4ac))/2a
For the equation you gave, a=1, b=19, c=88. Plug those numbers in and see what you get.
If you're confused by the +/-, it's shorthand for writing two things in one. There are usually two values of x that work, one with + and one with -.
2006-11-29 14:35:12
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answer #1
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answered by bictor717 3
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x^ 2 +19x + 88 = 0
(x +8)(x+11) = 0
8*11=88 8+11 = 19
x +8 =0 x+11 = 0 (solve for x)
-8 =-8 -11 = -11
x= -8 x= -11
Then place -8 in place of x to see if -8 is a solution for the equation
Next place -11 in place of x to see if -11 is a solution for the equation
Both -8 and -11 will work out
EX. X^2 +19X + 88 = 0
-8^2 + 19(-8) +88 =0
64 -152 +88 =0
0 = 0
X^2 + 19X +88 = 0
-11^2 +19(-11) +88 = 0
121 - 209 +88 =0
0 =0
2006-11-29 14:46:46
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answer #2
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answered by amckinney64 2
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Try factoring first. Put x's in the left position of each parenthesis. (x )(x )=0. This produces x^2. Now two numbers when multiplied give 88 and add up to 19 are-- 8 and 11. So (x+8)(x+11)=0. Set each ( ) = 0 and you get x+8=0 and x+11=0. The answers are x= -8 and x= -11. This is the FOIL method. First, Outer, Inner and Last terms!
2006-11-29 14:49:37
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answer #3
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answered by Nellie 1
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This one is easy to factor out. Basically, you need two numbers that when multiplied give 88, but when added give you 19. (8 and 11 work)
(x+8)(x+11)=0
Now take each piece and set it to zero, then solve for x. You will have two answers. TEST them both, one at a time in the original equation. Sometimes you end up w/one of them that doesn't work, but that's ok.
2006-11-29 14:35:24
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answer #4
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answered by Anonymous
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x=[-b(+ or -) the square root of b squared - 4ac]/2a
If that makes sense.
a represents the variable next to x^2, which in this case is 1. b represents the number next to x, which here is 19. c represents the number with no variables, which here is 88. You plug these into the equation, and you will eventually get two possible answers: one where you used a plus on top and one where you used the minus.
Hope this helps.
2006-11-29 14:38:17
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answer #5
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answered by Adriana 4
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