x2+kx-36
x squared + kx - 36
2006-11-29 14:28:14 · 4 answers · asked by #2 Football Fan 2 in Education & Reference ➔ Homework Help
need help solvn no need to explain...
please
2006-11-29 14:31:52 · update #1
need to find "k"
2006-11-29 14:33:30 · update #2
(x+6)(x-6)= x^2+6x-6x-36= x^2-36
so k should be equal to 0. k=0
2006-11-29 14:41:19 · answer #1 · answered by hockey 2 · 0⤊ 0⤋
It is not possible to "solve" this because it is simply a mathematical expression, not a mathematical equation. It is only one half of an equation, it needs to be set equal to something else in order to have a solution.
However, since it looks like part of a quadratic equation, I'll aproach it as such.
A quadratic equation is an equation in the form "ax^2 + bx + c = 0" -- in such an equation, the value of x can be found using the quadratic formula:
x = [-b +- (sqrt(b^2 - 4ac))] / 2a
In this case, a = 1, b = "k", and c = -36
so,
x = [-k +- (sqrt(k^2-{4*1*-36})] / 2a
x = [-k +- (sqrt(k^2-{-144})] / 2(1)
x = [-k +- (sqrt(k^2+144)] / 2
That "+-" means "plus or minus," in other words there are two solutions:
x = [-k + (sqrt(k^2+144)] / 2
and
x = [-k - (sqrt(k^2+144)] / 2
2006-11-29 22:46:14 · answer #2 · answered by Mustela Frenata 5 · 0⤊ 0⤋
What do you want to do with x² + kx -36??
There's no question here!
2006-11-29 22:41:43 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
(x+6)(x-6)
x2+2*6*x-36
x2+12x-36
k = 12
2006-11-29 22:32:49 · answer #4 · answered by blue 1 · 0⤊ 0⤋