please help with an algebra problem!!?

Question

Given the following rational function:

4x^2-10x+6 / -2x+3

Find equations for vertiacl and horizontal asymptotes.

Answer 1

Let y = (4x^2 - 10x + 6) / (-2x + 3)

The numerator can be factored as :
(-2x + 3)(-2x + 2)

Then, the factors (-2x + 3) in both numerator
and denominator can be cancelled, provided
that -2x + 3 ≠ 0, that is, x ≠ 3/2.

Thus, we get : y = -2x + 2 (where x ≠ 3/2)

This is the equation to a straight line
with the single point (3/2, -1) missing.
(If x = 3/2, then y = -2(3/2) + 2 = -1)

I guess the asymptotes must be at this point,
because the line gets closer and closer to it,
from both sides, but never reaches it exactly.

So vertical asymptote is at x = 3/2
and horizontal asymptote is at y = -1.

Answer 2

is 4/5-6