algebra Q's.....Please HelP!!!!!!!!?

Question

how do u solve:

x(x+3)(x-1)(x+4)(x-7)=0

?????? im not sure(whoever helps me the best and first gets 5 stars!)

Answer 1

x times x is not 2x but is x squared.

(x2 + 3x)(x-1)=x3-x2+3x2-3=x3+4x2-3
(x+4)(x-7)=x2-7x+4x-28=x2-3x-28
(x3+4x2-3)(x2-3x-28)=x5-3x2-28x2+4x4-12x3-112x2-3x2+9x-84

I believe the answer should be x5+4x4-12x3-146x2+9x-84

Answer 2

Whenever you multiply anything by 0, it's equal to 0.

Therefore, if the first X is 0 and you are multiplying everything else by 0, it becomes 0.

The answer is 0

Also note that it's an equation, with x being unknown. therefore, the answer that you are seeking is the value of the unknown (the x).

0 isn't the only answer, however. i did forget about the other ways of making the equation true.

Answer 3

if A*B*C*D*E = 0 then
A = 0 or B=0 or C=0 or D=0 or E=0
so in this case :
x=0 or x=-3 or x=1 or x=-4 or x=7

Answer 4

distribute
take it one at a time
x(x+3)
multiply x times x which is 2x and x times 3 which is 3x
so now the problem is
2x+3x(x-1)(x+4)(x-7)=0
2x plus 3x is 5x so........
5x(x-1)(x+4)(x-7)=0
so keep on distributing and you will get the answer

go to www.math.com for homework help

Answer 5

First foil (x+3)(x-1)
(x^2+2x-3)

Then foil (x+4)(x-7)
(x^2-3x-28)

Then distribute them together (x^2-3x-28)(x^2+2x-3)
x^4 + 2x^3 - 3x^2
- 3x^3 - 6x^2 - 9x
- 28x^2 - 56x + 84
-------------------------------------------------------------------
x^4 - x^3 - 37x^2 - 65x + 84

Don't forget the x from the beginning of the equation.
x(x^4-x^3-37x^2-65x+84)
=

x^5-x^4-37x^3-65x^2+84x

There ya go, that's the answer.
Vote for me please.