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a swimming pool 5 m wide by 10 m long is filled to a depth of 3-m. what is the pressure on the bottom due only to water?

I am trying to use the formula P=pgh. Where g=9.81 m/s2 and i assume H equals 3. I know the answer is 3x10^4 Pa. So do I just need to look up the density of the water or am i missing a step?

2006-11-29 12:56:45 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

Yesn its only water because really all it is, is the weight of water pushing down on you.

2006-11-29 12:59:19 · answer #1 · answered by DJ C 4 · 0 0

Well, I'm a scuba diver and we use the formula: 10 meters = 1 atmosphere,
1 atmosphere is 14 pounds per square inch.

So, at the surface the pressure is 14 pounds/square inch.
3 meters deep, the pressure is another 1/3 of an atmosphere, or about 14+14/3, or 19 pounds per square inch.
But the question was simply "due to the water", so the answer is about 14/3 pounds per square inch.

The TOTAL pressure on the bottom of the pool, is 14/3 times the area of the bottom of the pool.
5 m x 10 m is 50 square meters, or 50*39*39 square inches.

So the TOTAL pressues is about 14/3*50*39*39.

2006-11-29 21:10:31 · answer #2 · answered by firefly 6 · 0 0

i just did that math and 1x9.81x3 does not give you 3.10^4

2006-11-29 21:10:08 · answer #3 · answered by benzene boy 1 · 0 0

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