How can I leave the " X " by itself?
2006-11-29 10:28:11 · 5 answers · asked by yunito 1 in Science & Mathematics ➔ Astronomy & Space
To get x by itself in an inequality, divide the side with x by the constant (the nonvariable) next to it. So here, you would divide both sides of the equation by -2/5, which is the same thing as multiplying both sides by -5/2 (reciprical). This will cancel out the -2/5 next to the x, so 6 * -5/2 = -15. Also, when multiplying or dividing an inequality by a negative, you switch the "<" or ">" sign to the opposite sign. therefore, x< -15.
2006-11-29 10:41:37 · answer #1 · answered by J.J. 3 · 0⤊ 0⤋
You can perform operations on an inequality just as you can on an equality. Divide both sides of this inequality by -2/5 (same as multiplying by -5/2)
Yields x>6 x -5/2, or x > - 15.
2006-11-29 19:12:48 · answer #2 · answered by JIMBO 4 · 0⤊ 0⤋
Multiply both sides by -5/2
X > -15
2006-11-29 18:36:12 · answer #3 · answered by rentaprogrammer 2 · 0⤊ 0⤋
mul -5/2 from both sides
x<-15
2006-11-29 18:34:40 · answer #4 · answered by 7 · 1⤊ 0⤋
You multiply both sides by the reciprocal (flip) of the fraction.
2006-11-29 18:38:53 · answer #5 · answered by T'Vral 3 · 0⤊ 0⤋