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Fe2O3(s) + CO(g)----> Fe(l) + CO2(g)
How many grams of Fe2O3(s) will be required to produce 5.90 moles of Fe(l)?balance the equation first

2006-11-29 09:25:37 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

This is the smelting of Iron (III) oxide to metalic Iron using coke gas. The balanced equation is:

Fe2O3 (s) + 3 CO (g) ---> 2 Fe (l) + 3 CO2 (g)

One mole of oxide produces 2 moles of Iron. If 5.90 moles of Iron is produced, then 5.90/2 moles of oxide is needed.

The moles needed times the molecular mass of the oxide will give you the grams of oxide needed. The molecular mass of Iron (III) oxide is 159.69 g/mol.

2006-11-29 13:35:48 · answer #1 · answered by Richard 7 · 65 1

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