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50r=(e^20r)-1

Find the value of r.

2006-11-29 08:10:00 · 5 answers · asked by Anonymous in Education & Reference Homework Help

5 answers

Was it urgent the four other times you asked this question?

2006-11-29 08:12:07 · answer #1 · answered by Anonymous · 0 0

50r=(e^20r)-1 so hmm

so e^20 *r or e^(20r)

I like (e^20)(r) so....divide by r both sides

50=((e^20))-(1/r) then add 1/r and minus 50

(1/r)= (e^20)-50 then times by r

1=r((e^20)-50) sooo.. divide and

1/((e^20)-50))=r

Now if its e^(20r) i dont remember its been a few years since calculus.....

2006-11-29 08:21:56 · answer #2 · answered by im1canadain 3 · 0 0

Are you requesting (2^8*3^8)^(2^8*3^8) * (2^12 *3^6)^(2^12*3^6) ? 2^8*3^8 = 6^8 2^12 = 4^6 2^12*3^6 = 4^6*3^6 = 12^6 so which you have (6^8)^(6^8) * (12^6)^(12^6) What do you choose it simplified to?

2016-12-14 09:06:44 · answer #3 · answered by pfeifer 4 · 0 0

the answer is r=1/10(e^2-5)

2006-11-29 08:20:42 · answer #4 · answered by bell 4 · 0 0

i got r= about 2.06x10^-9. i hope that's right, i'm almost positive.

2006-11-29 08:27:28 · answer #5 · answered by s.allen341 1 · 0 0

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