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Cal has a six sided die labeled 1 through 6. If he throws it 30 times, how many times should he expect to roll a number less than 3?

2006-11-29 08:03:46 · 5 answers · asked by Claudia R 1 in Education & Reference Homework Help

5 answers

Wow you're a dumbass

2006-11-29 08:05:41 · answer #1 · answered by Anonymous · 0 1

since there are two numbers lower than 3 then its 2/6 which is 1/3 of 30
1/3 *30=10

2006-11-29 08:13:53 · answer #2 · answered by bell 4 · 0 0

< 3 = 1 or 2. 1 or 2 are 2/6 or 1/3 of the possible dice rolls. In theory, the probability that either 1 or 2 comes up is 1/3 of the time, or ten of those 30 times.

2006-11-29 08:06:58 · answer #3 · answered by Cobalt 4 · 1 0

there are to numbers less than three so 2/6 times or 1 out of every three rolls, 30 x (1/3) = 10
10 times

2006-11-29 08:07:31 · answer #4 · answered by blah 2 · 0 0

10 Each number should come up 5 times 5x6=30

2006-11-29 08:06:10 · answer #5 · answered by jaws65 5 · 0 0

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