2006-11-29 07:26:39 · 10 answers · asked by J 2 in Society & Culture ➔ Cultures & Groups ➔ Other - Cultures & Groups
There is not enough money in the world for that to happen with me.
2006-11-29 07:29:12 · answer #1 · answered by Sugar 7 · 1⤊ 1⤋
Hmmm, the problem is that these tapes show up later in your life and can cause a whole lot of trouble, in regard to getting a job, getting a girlfriend who finds out and is less than happy with it, your mom sees it or something along these lines.
But to amuse you... I'll say about $1000 (naturally she must be 100% disease free AND on a contraceptive).
I'd only ask that much as a persuasive for me as there would be all these other people around while you're banging her (director, cameraman, etc).
2006-11-29 07:42:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
$25
2006-11-29 07:28:15 · answer #3 · answered by Anonymous · 0⤊ 1⤋
If I wasn't married, and It involved getting to have sex with a girl like Courtney Cummz, then no payment would be needed. I would even pay to get to the shooting location. And, I would pay my own room and board and food. Come on
2006-11-29 23:18:44 · answer #4 · answered by Carlson 3 · 0⤊ 0⤋
$ 1,500 per diem for every day of principal photography, 1% of the gross & 6 months of Screen Actors Guild health insurance coverage.
2006-11-29 07:29:28 · answer #5 · answered by Anonymous · 0⤊ 0⤋
No money in the world is enough if it involves sexual acts.
If it was some very weird porn movie where I didn't have to do anything 'strange' maybe a few hundred thousand :P
2006-11-29 07:29:48 · answer #6 · answered by confused 1 · 0⤊ 3⤋
$8, free rent on the railroads, and a "Get Out of Jail Free" card.
2006-11-29 07:28:56 · answer #7 · answered by ? 6 · 1⤊ 1⤋
No more than 100 bucks, any more and I won't pay : P
2006-11-29 07:33:04 · answer #8 · answered by cedykeman1 6 · 0⤊ 0⤋
$40,000, plus free health insurance for life.
2006-11-29 07:30:51 · answer #9 · answered by kent_shakespear 7 · 0⤊ 0⤋
At least 500 dollars!!!
2006-11-29 07:29:59 · answer #10 · answered by Webballs 6 · 0⤊ 1⤋