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2006-11-29 07:06:48 · 17 answers · asked by Tammy M 2 in Science & Mathematics Mathematics

17 answers

No, it is 0.

4*-2^2 is 16
8*-2 is -16
3*-2 is -6
6 is 6

16+(-16)+(-6)+6 = 0

2006-11-29 07:09:09 · answer #1 · answered by Blunt Honesty 7 · 0 0

No. It's 0.

You have to follow the order of operations:
I. powers and radicals (roots)
II. multiplications and divisions
III. additions and subtractions

Here is the solution (sorry, I can't display a sign for power, so we have to improvise a bit):
4*(-2)*(-2) + 8*(-2) + 3*(-2) + 6 = 4*4+ (-16) + (-6) + 6
= 16 - 16 - 6 + 6 = 0
As you see, we first multiplied what we could, with respect to their signs. Result: 4*4+ (-16) + (-6) + 6
Then we used the rule of multiplying positive and negative signs. (Remember, it is the same as if we had:
4*4+1*(-16)+1*(-6)+6
Result: 16 - 16 - 6 + 6. Since you have two pairs of same absolute value, but with different signs, it is pretty obvious that 16 and -16 cancel each other, just like -6 and 6. So you get 0 + 0 = 0.
The other way we could do this is to sum up all the "plus" numbers and all the "minus" numbers, then calculate the result: 16+6+(-16)+(-6) = 22 - 22 = 0.

2006-11-29 15:41:53 · answer #2 · answered by Mirta G 2 · 0 0

No, The answer is zero.

4(-2)² + 8(-2) + 3(-2) + 6

= 4(4) + -16 + -6 + 6
= 16 - 16 + 6 - 6
= 0 + 0 = 0

2006-11-29 15:11:14 · answer #3 · answered by halley 1 · 0 0

4(- 2)² + 8(- 2) + 3(- 2) + 6 =

4(4) + (-16) +(- 6) + 6 =

16 - 16 - 6 + 6 =

Adding the positives and adding the negatives

22 - 22 = 0

0 = 0

- - - - - -s-

2006-11-29 16:01:53 · answer #4 · answered by SAMUEL D 7 · 0 0

No its not 48 its 0

2006-11-29 15:16:47 · answer #5 · answered by soul_tamer 3 · 0 0

Remember the order of operations - the exponent first.
4 * (4) - 16 - 6 + 6 = 16 - 16 - 6 + 6
The +16 and - 16 cancel out, as well as +6 and -6, so the final answer is 0.

2006-11-29 15:12:22 · answer #6 · answered by j 4 · 0 0

It helps if you use the order of operations. Here is the order that you should always follow:
1. (parentheses) <--anything in parentheses should be solved first.
2. exponents
3. multiplication and division
4. addition and division

so in this case, there are parentheses. However, there is nothing that needs to be solved within the parentheses because they are just numbers. You would need to solve the parentheses first if it was (4-2), for example. so next is exponents.
(-2)^2 is 4
next is multiplication
8*(-2) = -16
3*(-2) = -6
so putting it all together:
4*4 + (-16) + (-6) + 6 = 0

2006-11-29 15:17:14 · answer #7 · answered by Lauren 2 · 1 0

Here is the solution:

We have:

4x(-4) - 16 - 6 + 6 =

16 -16 - 6 + 6 = 0

2006-11-29 15:13:19 · answer #8 · answered by Anonymous · 0 0

The answer is 0. 8( -2) = -16 etc. You were going 8-2 which isn't right.

2006-11-29 15:16:02 · answer #9 · answered by Christabelle 6 · 0 0

No, it's 0

2006-11-29 15:14:01 · answer #10 · answered by Morena461 2 · 0 0

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