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Can i get the steps for solving?

[H30+] = 1.0 x 10 -4M

[H30+] = 3.0 x 10 -9 M

2006-11-29 05:37:16 · 3 answers · asked by chemistrymagic 1 in Science & Mathematics Chemistry

3 answers

pH= -log([H30+])


just put the #'s in the above eqn.

for pOH, its pOH= -log([OH])
and for pH given [OH], its pH= 14 - (-log([OH])

2006-11-29 05:55:36 · answer #1 · answered by annie*bananie 2 · 0 0

a answer has a pOH of two.00. what's the [H+] and [OH-]? a million.0 x 10-11, a million.0 x 10-3 a million.0 x 10-12, a million.0 x 10-2 a million.0 x 10-7, a million.0 x 10-7 a million.0 x 10-2, a million.0 x 10-12 a million.0 x 10-10, a million.0 x 10-4

2016-12-14 09:00:53 · answer #2 · answered by ? 4 · 0 0

Simple - put these numbers into your calculator, and apply the negative logarithm function.
Different calculators do this in different ways, unfortunately.

2006-11-29 05:40:16 · answer #3 · answered by Gervald F 7 · 0 0

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