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2006-11-29 05:26:48 · 3 answers · asked by moooona1987 2 in Science & Mathematics Mathematics

3 answers

Assuming it is x - 2/x^2+x^4

So, x - 2/x^2(1+x^2) = x - 2[1/x^2 - 1/(1+x^2)]

Its integral is x^2/2 +2/x + 2 atan(x) + C

2006-11-29 05:45:52 · answer #1 · answered by ag_iitkgp 7 · 0 0

3x-6/x^3+5x-10/x^5. I am not sure how to treat the denominators of the two fractions. One is x^3 and the other is x^5

(3x-6/x^3) + (5x-10/x^5)

2006-11-29 05:41:07 · answer #2 · answered by Tony T 4 · 0 0

difficult
ill post this tomorrow , ill look up in my maths book,
there is a formula for ∫ (x - a /( x^2 + x^4)dx)
ill look up

2006-11-29 05:27:56 · answer #3 · answered by Aqua 4 · 0 0

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