This is a simple FOIL problem:
To multipy binomials you have to multiply using FOIL or First, Outer, Inner, Last.
(x+3)(2x-1)
(x*2x)+(x*-1)+(3*2x)+(3*-1) -> First terms, outer terms, inner terms, and last terms
You'll end up with:
2x^2 + -x + 6x - 3
=2x^2 + 5x - 3
2006-11-29 05:23:48
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answer #1
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answered by Anonymous
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(x + 3) (2x - 1) =
= x(2x) + x(-1) + 3(2x) + 3(-1)
= 2x^2 - x + 6x - 3
= 2x^2 + 5x - 3
2006-11-29 13:39:13
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answer #2
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answered by rush 2
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x (2x - 1) + 3 (2x -1)
2x squared - x + 6x - 3
2x squared +5x - 3
theres ur answer i think! (squared means put a little 2 on the pper right corner of 2x...)
2006-11-29 13:26:35
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answer #3
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answered by Damien 3
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Multiply each term of 1st binomial by each term of 2nd:
x(2x) + x(-1) + 3(2x) + 3(-1)
2x² -x + 6x - 3
2x² + 5x -3
2006-11-29 13:23:48
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answer #4
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answered by Philo 7
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(x+3)(2x-1)
=2x^2-x+6x-3
=2x^2+5x-3
2006-11-29 13:25:41
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answer #5
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answered by simple_life726 1
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Use the "FOIL" guide - first, outside, inside, last.
2x^2 -x +6x - 3
2x^2 +5x -3
2006-11-29 13:23:52
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answer #6
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answered by quatrapiller 6
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2x^2 - 6x - 3
2006-11-29 13:22:59
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answer #7
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answered by Myndlynd T 2
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as you already know.. elvis... the answer is...
x is elvis... so 2x-1 on the +3 would mean the Apocalypse.
2006-11-29 13:28:40
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answer #8
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answered by Anonymous
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Ah, classic binomial. FOIL it! That's first terms, inside terms, outside terms and last terms multiplied together and then added to one another.
2006-11-29 13:22:35
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answer #9
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answered by DJL2 3
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2x2+5x-3 the two after x is squared i think its right anyway = s
2006-11-29 13:24:55
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answer #10
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answered by jak 3
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