2006-11-29 04:24:46 · 5 answers · asked by tigertank702 1 in Education & Reference ➔ Homework Help
Let the integers be x, y, z.
1: z = y + 1
2: y = x + 1
3: x * z = 15
from 1:
z = (x + 1) + 1
z = x + 2
now from 3:
x * (x + 2) = 15
x^2 + 2x = 15
x^2 + 2x - 15 = 0
(x-3)(x+5) = 0
so x=3 or x=-5 but x is positive
so x = 3
.... or you could just think about a sec and come up with it.
2006-11-29 04:30:03 · answer #1 · answered by scruffy 5 · 1⤊ 0⤋
How about 3, 4 and 5?
Why? You have to solve the equation x(x+2) = 15.
So x² + 2x -15 = 0
(x-3)(x+5) = 0.
Since x is positive, we must have x = 3.
2006-11-29 14:47:33 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
3, 4, 5... 3*5 = 15.
I feel guilty answering these for you if indeed these are your homework questions. I'm sure if you take a moment or two to think it through you can do it on your own.
2006-11-29 12:32:31 · answer #3 · answered by Arletta S 3 · 0⤊ 0⤋
There should be a formula for this, but I can only do trial and error:
1,2,3 .....1*3 <15
2,3,4 .......2*4 <15
3,4,5 .....3*5 =15
4,5,6 .... 4*6> 15
The nos. are 3,4,5
2006-11-29 12:43:49 · answer #4 · answered by peaceman 4 · 0⤊ 0⤋
3,4,5
2006-11-29 12:27:21 · answer #5 · answered by ? 3 · 0⤊ 0⤋