positive root of the equation 3x^2 = 27?

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positive root of the equation 3x^2 = 27?

2006-11-29 04:17:29 · 4 answers · asked by tigertank702 1 in Science & Mathematics ➔ Mathematics

4 answers

3x^2=27
x^2=9
x= +- 3 ==> positive root : x=3

2006-11-29 04:20:35 · answer #1 · answered by Behnam B 1 · 1⤊ 0⤋

2006-11-29 12:19:24 · answer #2 · answered by Tiguerón 1 · 0⤊ 0⤋

3x^2 = 27

x^2 = 9

x = +3 or -3

ans = +3

2006-11-29 12:27:18 · answer #3 · answered by george t 2 · 0⤊ 0⤋

Above people are correct, it's +3.

3x^2 = 27
so divide both sides by 3
x^2 = 9
then do square root
x = + or - 3
but you want the positive root
so = +3

2006-11-29 12:25:33 · answer #4 · answered by snowpatrol161 2 · 0⤊ 0⤋