I am having problems balancing this
KI+HNO3=KNO3+NO+I2+H2O
2006-11-29 03:05:45 · 5 answers · asked by steven11111958 1 in Science & Mathematics ➔ Chemistry
The coeffcients are 6 , 8 = 6 , 2, 3, 4.
Notice that the iodide ion is being oxidized to elemental iodine as a couple of nitrates are being reduced.
2006-11-29 03:45:04 · answer #1 · answered by docrider28 4 · 1⤊ 0⤋
KI+HNO3=KNO3+NO+i2+H2O > 6KI+8HNO3=6KNO3+2NO+3I2+4H2O
I usually multiply by 12 and then divide by a common denominator.
12 because it contains:1,2,3,4,6 and 12.
But if it doesnt work try 24 or 36.
In this case 24.
2006-11-29 11:58:09 · answer #2 · answered by Yahoo! 5 · 1⤊ 0⤋
Go to the periodic table
2006-11-29 12:01:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
o_o
i forgot how to do that.
good luck though
2006-11-29 11:12:51 · answer #4 · answered by Pwnzer 4 · 0⤊ 0⤋
6KI+8HNO3 --> 6KNO3+2NO+3I2+4H2O
2006-11-29 12:39:23 · answer #5 · answered by ☮Luwayla☮ 6 · 0⤊ 0⤋