c^2 - 6c = 27
2006-11-29 03:03:25 · 5 answers · asked by mzmuffin40155 2 in Science & Mathematics ➔ Mathematics
add 9 on both sides
(c-3)^2 = 36
c-3 = 6 to take positvie value
c= 9
2006-11-29 03:05:36 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
c^2 - 6c = 27
c^2 - 6c - 27 = 0
c^2 + 3c - 9c - 27 = 0
c(c+3) - 9(c+3) = 0
(c+3) (c-9) = 0
c= -3 or c = 9
Positive root is 9
2006-11-29 03:08:39 · answer #2 · answered by Sayee 4 · 0⤊ 0⤋
c² - 6c = 27
c² - 6c - 27 = 27 - 27
c² - 6c - 27 = 0
(c - 9)(c + 3)
The roots
c = 9
c = - 3
- - - - - -s-
2006-11-29 03:40:08 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
c^2-6c-27=0
c^2-9c+3c-27=0
c[c-9]+3[c-9]=0
[c+3][c-9]=0
we have two roots
c+3=0
c=-3
c-9=0
c=9 is the positive root
2006-11-29 03:15:04 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
6 + sqrt(36 + 4*27)
2006-11-29 03:09:43 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋