the sum of two consecutive positive integers is 85. Find the integers?

Answer 1

two consecutive numbers could be called x, and (x+1). Add these two together to find the sum. x+(x+1) = 85.
So 2x+1 = 85.
subtract 1 from both sides and we have 2x = 84.
Divide both sides by two to get x by itself so x = 42.
So if x=42, the consexutive numbers from the beginning of the problem would be 42, and 43.

Answer 2

Let x = first integer then (x + 1) = 2nd integer x² + (x + 1)² = 85 x² + x² + 2x + 1 = 85 2x² + 2x - 84 = 0 Divide thru by 2 x² + x - 42 = 0 factor (x + 7)(x - 6) = 0 Discard trivial negative solution x = 6 x + 1 = 7 The two integers are 6 and 7 .

Answer 3

Let
x= the first consecutive integer

x + 1 = the second consecutive integer

85 = The total integer

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The equation

x + x + 1 = 85

2x + 1 = 85

2x + 1 - 1 = 85 - 1

2x = 84

2x/2 = 84/2

x = 42

The answer is x = 42

Insert the x value into the equation

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Check

x + x + 1 = 85

42 + 42 + 1 = 85

42 + 43= 85

85 = 85

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The two integers are 42 and 43

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Answer 4

X+Y = 85
X+1 + X = 85
2X + 1 = 85
X = 42
Therefore, the required integers are 42 and 43

Answer 5

42 and 43

Answer 6

42 and 43

Answer 7

(x+1)+(x)=85, solve for x
x is the first integer, x+1 is the second.

Answer 8

x and x+1
add and get 2x+1 = 85
x= 42
numbers are 42 and 43