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4 answers

all you do is break KOH into it's ions which makes the solution basic

2006-11-29 04:06:35 · answer #1 · answered by shiara_blade 6 · 0 0

a more dilute solution of potassium hydroxide, and possibly a little heat if the original solution is superconcentrated - that is, if it has any free potassium. (HINT: "hydroxide" IS water!)

2006-11-29 02:49:49 · answer #2 · answered by Jim H 1 · 0 0

K+ -OH + H-O-H <----> H-O-H + K+ -OH
Notice that you get the strong base (-OH) removing a H off the water in the starting material. This is an equilibrium reaction.

2006-11-29 02:45:53 · answer #3 · answered by Peter B 3 · 0 0

potassium hydroxide is KOH and water is H2O so you use double displacement... i learned this a while ago, i don't remember how to use double displacement.

2006-11-29 02:45:40 · answer #4 · answered by ♥heartbroken♥ 3 · 0 0

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