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Question

A 3.00-g sample of an alloy (containing only Pb and Sn) was dissloved in nitric acid (HNO3). Sulfuric acid was added to this solution, which precipitated 2.39 g of PbSO4. assuming that all of the lead was precipitated, what is the percentage of Sn in the sample? (molar mass of PbSO4= 303.3 g/mol)

Answer 1

let write the reaction of plumb nitrate

Pb (NO3)2 + H2SO4 ---> PbSO4 + 2 HNO3

the molarity of PbSO4 is 2.39/303.3=0.00789

the atomic mass of Pb is (303.3-96) =207.3
(I have substacted 96 the mass of SO4 to PbSO4, to find that of Pb)

the mass of Plumb is 1.63g

And the mass of Sn is 3-1.63 = 1.37 g