1. On Sally's way to her friend's house, the speedometer of the car reads 45kph. Sally left home exactly 9:00 in the morning. She arrived at 11:00 a.m. How far did she travel?
2. Find the average speed of a car if it travels at a distance of 100 km for 2 hours and continued another distance of 108 km for 3 hours!
You must have your solution!
2006-11-29 00:54:59 · 12 answers · asked by ? 3 in Science & Mathematics ➔ Mathematics
1) two hours from 9 to 11. so distance 45*2 = 90 km
2) The car has done 100+108= 208 km in 5 hours
the speed is 208/5 = 41.6 kph
2006-11-29 00:59:17 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
1. 90 km, if and only if the speedometer was reading 45 kph the whole time. If she had to start the car from 0 to 45 and stop the car from 45 to 0, she traveled slightly less than 90 km.
2. If you're saying it was 100 km/hr for 2 hrs and 108 km/hr for 3 hours, then the average is 100*2 + 108*3 = 524/5 hrs = 104.8 km/hr. If you're saying the car traveled a total DISTANCE of 100 km in 2 hrs and 108 km in 3 hrs, then it went 208 km/5 hrs = 41.6 km/hr.
2006-11-29 00:58:37 · answer #2 · answered by rd211 3 · 0⤊ 0⤋
1. 90 kilometers. 45 kph times 2 hours.
2. The car went 50 kph for 2 hours (100 hm/2 hours) and then 36 kph for another 3 hours (108 km/3). You average it by adding the hourly speeds and then dividing by the total time driven:
(50+50+36+36+36)/5=208/5
41 and 3/5 kph, or
41.6
Now, if these were easy why did you ask me? :P
2006-11-29 00:59:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1. 2 hrs x 45 kph = 90 km
2. (100 + 108 km) / 5 hrs = 41.6 kph
2006-11-29 01:00:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the first question is algebra to remedy for x. 4x - 2 = 2x + 5 2x = 7 x = 7/2 the 2d question asks, "ellie,fran,gina,and holly are status unmarried record in line for lunch. If holly is both 0.33 or fourth, in what percentage approaches can the 4 females be status in line, and why? If Holly might want to correctly be status in any of the places, the reply is 4*3*2 = 24 accessible mixtures. If holly is in the third position, then there are 3 positions that would want to replace, and there are 3*2 = 6 opportunities. If holly is in the 4th position, then there are 3*2 = 6 opportunities. hence, there are a complete of 12 accessible mixtures for the girls to be lined up in line if Holly is constrained to being in both the third or 4th position in line.
2016-10-07 23:04:46 · answer #5 · answered by ? 4 · 0⤊ 0⤋
1. Travel time is 2 hours. Rate is 45 mph.
D = RT
D = 45 * 2
D = 90 miles
2. Total distance = 208km, Total time = 5 hours
R = D/T
R = 208 / 5
R = 41.6 kph
2006-11-29 01:07:43 · answer #6 · answered by Puzzling 7 · 0⤊ 0⤋
a) 90 km
b) (100+108) divide (2hours+3hours)=41.6 / 50km+36km=86km
2006-11-29 01:04:41 · answer #7 · answered by ErC 4 · 0⤊ 0⤋
1...90 km
2...208/5 = 41.6
2006-11-29 00:59:54 · answer #8 · answered by Anonymous · 0⤊ 0⤋
a) 90 km
b) 41.6 kph
2006-11-29 00:58:09 · answer #9 · answered by Matthew H 3 · 0⤊ 0⤋
If are 2 easy math questions, you should answered.
Bye!
2006-11-29 01:03:34 · answer #10 · answered by Anonymous · 0⤊ 1⤋