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find slope of line that passes through each pair of points

(-5,4), (-5,-1)
(-2,3),(8,3)
(-8,3),(-6,2)

2006-11-28 23:03:44 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

First pair both x values are the same so it is a vertical line through -5 on the x-axis. Which would mean it has no slope (undefined)

Second pair has identical y-values so it is a horizontal line (slope=0) through 3 on the y-axis

For the third pair us the formula
y=mx+c which describes any straight line (m=slope, c= a constant distinguishing the line from others with the same slope in different locations on a graph)
3=m(-8)+c (a)
2=m(-6)+c (b)
Simultaneous equations!
c=3+8m (a)
2=-6m+3+8m (sub (a) into (b))
2m=-1
m=-1/2
So the slope = -1/2

This formula can be used for any problem like this using the same method.

2006-11-28 23:21:46 · answer #1 · answered by Peter 3 · 1 1

the formulae fpr the slope of line is
m=(y_2 - y_1)/(x_2 -x_1)

hence
slope of line passing thru (-5,4),(-5,-1)
= (-1-4)/(-5-{-5}) = -5/0 = infinite
it means the line is perpendicular to the x-axis

slope of line passing thru (-2,3),(8,3)
=(3-3)/(8+2) = 0
it means the line is parallel to the x-axis

slope of line passing thru (-8,3),(-6,2)
=(2-3)/ (-6+8) = -1/2

2006-11-29 07:18:35 · answer #2 · answered by ashish.prshr 2 · 0 0

First line parallel to y axis slope infinite through the abcissa -5

Second line line parallel to x axis slope infinite through the ordinate 3

write: 3 = -8 a +b ; 2 =-6a +b solving a=-1/2 b=-1
line y = -0.5x-1

2006-11-29 07:14:37 · answer #3 · answered by maussy 7 · 0 0

aren't u soppose to create a two arrows crossing each other. each arrow is a time line. to go -5 u start at 0 and count down to -5 and across 4 and thats your first point. than u go to -5 and -1 and that is your second point.

i wish i was able to draw it for u online, its pretty simple.

2006-11-29 07:14:52 · answer #4 · answered by Miki 6 · 0 0

Isn't the slope the difference in the y coordinates divided by the difference in the x coordinates ??? I'm sure you can do the arithmetic.

2006-11-29 07:18:13 · answer #5 · answered by Gene 7 · 0 0

If i am not mistaken you are suppose to plot the points on the axies.
and then draw the slop

2006-11-29 07:12:53 · answer #6 · answered by Osunwole Adeoyin 5 · 0 0

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