ab ef jk qr ?

Question

what would be the next combination in that sequence

Answer 1

wx.. i dont think u need explaination..

After ab 2 space.. 2 has 3 letters so..
after ef .. 3 space..3 has 5 letters so..
after jk.. 5 space... 5 has 4 letters so..
after qr........ it must be wx..

I can explain that way tooooo dear

Answer 2

ab are there
cd are not
ef are there
ghi are not
jk are there
lmnop are not
qr are there.

It looks like you are leaving out a prime number of letters each time. First 2, then 3, then 5. If this is the pattern, 7 letters should be left out next.

stuvwxy are left out.

Now I have a problem. The pattern appears to have two letters in after a prime number of letters is left out. But there's only one letter of the alphabet left - z.

Maybe you should start over with the alphabet? I'm not certain, but that's a reasonable suggestion.

With that in mind, I'd say that "za" comes next.

EDIT:

After looking back at some of the solutions, I will say that the 2,3,5,8 solution is also a good one.

Those are consecutive terms in the Fibonacci sequence, and so that's also a possibility. Prime numbers happened to be the first sequence that I saw.

Funny how these problems work out.

Answer 3

The Series wud be .....

ab ef jk qr za

as ----- between ab and ef ----> cd are missing (2 alphabets)
----- between ef and jk ----> ghi are missing (3 alphabets)
----- between jk and qr ----> lmnop are missing (5 alphabets)

2,3,5 is the series of prime numbers
no next prime number is 7
count 7 alphabets from r --- s t u v w x y -- the next two alphabets are z and a (countinued ring)

so answer is ----> the next combination in that sequence is "za"

Answer 4

ab..cd..ef..ghi..jk..lmnop..qr............
2 letters are skipped off between ab and ef,3 letters between ef and jk and 2+3=5 letters are skipped between jk and qr.
Therefore letters to be skipped in the series = 3+5 = 8
Final answer : ab

Answer 5

the next combination in this series is again
ab

BECAUSE
a b _ _ e f _ _ _ j k _ _ _ _ _q r _ _ _ _ _ _ _ _ ab
2 3 5 8
2+3=5
3+5=8

Answer 6

1. The letter pairs are adjacent
2. The pairs are separated by 2,3 and 4 letters respectively
3 Therefore, the next sequence will be separated by 5 letters
(s,t,u,v, w) and will be a pair (xy)

Answer: xy

Hope this helps!

Answer 7

xy

ab rank of letter 12 inthe alphabet
ef rank of letter 56 inthe alphabet difference in the alphabet order 4
jk rank of letter 10,11 inthe alphabet difference 5
qr rank of letter 17,18 inthe alphabet difference 6
xy rank of letter 24,25 inthe alphabet difference 6

Answer 8

ab

Answer 9

the answer is zA

Answer 10

i agree with cfpops