Calculate the percent yield (%)?

Question

For the reaction BaCl2 (aq) + ZnSO4 (aq) BaSO4 precipitates out.
Calculate the percent yield (%) if 16.775 g of BaSO4 precipitates
when 2.100 L of 0.0500 M BaCl2 (aq) and 1.920 L of 0.0456 M ZnSO4 (aq) are mixed.

Answer 1

BaCl2 + ZnSO4 => BaSO4 + ZnCl2

the moles of BaCl2 in the solution 0.05 * 2.1 = 0.105
the moles of ZnSO4 in the solution 0.0456 * 1.92 = 0.087552

because the moles of BaCl2 is greater than that of ZnSO4 so all the moles of ZnSO4 will react completely

the moles of BaSO4 produced if the percent yield is 100% : 0.087552
the grams of BaSO4 is produced with 100% of yield : 0.087552 * 233 = 20.399g

the percent yield is 16.775 / 20.399 *100% = 82.23%