What is the final molarity of KOH in the 100. mL flask ?

Question

A student prepares a solution by dissolving 5.98 g of KOH in enough water to make 250. mL of solution.
The student then transfers 27.0 mL of this solution into a 100. mL volumetric flask. Water is then added
up to the 100. mL mark.

Answer 1

the moles of KOH 5.98/56 = 0.107 moles
the molarity of the solution : 0.107/0.250 = 0.427M

the moles of KOH in 27mL of the solution 0.427 * 0.027 = 0.011529 moles
the final molarity : 0.011529/0.1 = 0.11529 M