Evaluate the Integral?

Question

The integral of (x + (15/(sin^2(x)))) from pi/6 to pi/2
give the answer in exact form. type pi for pi.
clarify:
∫x+[15/(sin^2(x))] dx [(pi/6), (pi/2)]
Thanks everybody!! :)

Answer 1

Integral of 1/sin^2(x) = - cotang(x) = - cos(x)/sin(x). Then your integral is: [x^2/2 - 15 cos(x)/sin(x)] from pi/6 to pi/2 = pi^2/9 + 15cos(pi/6)/sin(pi/6).