the incline is 200 m and the vertical height gained in moving this distance is 20 m. What is the magnitude of the force F if friction is negligible? (Assume g = 10 m/s2)
2006-11-28 19:32:59 · 3 answers · asked by applekarim 1 in Science & Mathematics ➔ Physics
This is an energy balance situation. The work done in dragging the object must equal the energy change. In this case the energy is potential energy, given by m*g*∆h, where ∆h is the change in vertical distance. The work (energy) required to drag the block is force times distance along the incline. Equate these two quantities and solve for F.
2006-11-28 19:38:10 · answer #1 · answered by gp4rts 7 · 1⤊ 0⤋
angle of inclination, A= sin inverse (200/100)
F= 100(10) sinA
2006-11-29 03:38:44 · answer #2 · answered by ninjatortise 2 · 0⤊ 1⤋
gp4rts's answer is good.
ninjatort...'s answer has an error.
A= sin inverse (200/100) should be A= sin inverse (20/200)
2006-11-29 14:57:51 · answer #3 · answered by sojsail 7 · 0⤊ 0⤋