2006-11-28 19:25:42 · 4 answers · asked by applekarim 1 in Science & Mathematics ➔ Physics
You'll need to do your own homework.
2006-11-28 19:35:19 · answer #1 · answered by bestonnet_00 7 · 0⤊ 0⤋
well the force required to break the nut free would be 75N*m/25cm =300Newtons - assuming that the force applied to the wrench is perpendicular to the wrench. If it is not, you must take into account that not all of the force your exerting is being applied to the torque of breaking the nut free. you answer then would be (300/sin A) where A is the angle that the force makes with the perpendicular to the wrench.
2006-11-29 03:35:03 · answer #2 · answered by igot4onit 2 · 0⤊ 0⤋
I presume you are trying to find the force applied to the wrench?
It will 75Nm/.25m=300N
2006-11-29 03:30:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
for the love of jehova... post the questions completely, including what you want to know
2006-11-29 03:32:19 · answer #4 · answered by Finswimmer 2 · 0⤊ 0⤋