FIND ITS VELOCITY AND DISPLACEMENT AFTER 3.0 SECONDS?SHOW YOUR SOLU
TION
2006-11-28 18:29:02 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The stone has two componenst of velocity and displacement. The x component of velocity stays the same, and the x displacement is x-velocity times time. The y-velocity is g*t, acceleration times time, and the y displacement is ∫atdt = .5*a*t^2. The total vector velocity and displacement is the vector sum of the x and y components √[x^2+y^2]
2006-11-28 18:34:38 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
Duh! It depends how high the building is --- remind your teacher of that!
(If not high enough [HOW HIGH?!] the stone will have plowed into the ground! For example, this would certainly happen if the building was < 100 ft in height, which limits the falling time to 2.5 secs. Why don't you try to find the greatest height for which the stone will hit the ground --- presumed FLAT --- BEFORE 3 seconds have elapsed? )
Think; live long and prosper.
2006-11-28 18:50:40 · answer #2 · answered by Dr Spock 6 · 0⤊ 0⤋
It would be dropping at the rate of 96 feet per second by the time it had gotten 120 meters out.
2006-11-28 18:51:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Lol. Do your own homework.
2006-11-28 18:30:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋