Chemistry question?

Question

Got stuck on this in my revising!
An aqeous solution of bomine was added to an aqueous solution of chloride ions and also to an aquous solution of iodide ions.

State what you would see in each case, inlcude an equation for any chemical reaction that takes place, and explain the trend shown by these observations.

Thanks,
Harry

Answer 1

These are redox reactions. You can find out which reaction will occur by looking at the standard reduction potentials of each half reaction. Alternatively, this is a very simple case where you just need to compare the electronegativities, something very straightforward in this case since all the elements involved belong in the same group of the periodic table.

The putative reactions would have the general scheme:

Br2 + 2X- -> X2 + 2Br-
In order for this to happen, Br must be more electronegative than X so that it can steal the electrons away from X.
Electronegativity decreases as you go down the group of elements in the periodic table.
Having said that you just need to see which element is more electronegative (Cl or Br, I or Br) based on their positions in the periodic table to decide which reaction can take place and which cannot.

Answer 2

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Answer 3

I think the people before me are a bit confused. He's asking what will happen in EACH CASE. Not when you pour all three together. Since all three of the indicated elements are lacking 1 electron to complete their full shells, they are seeking to bond with another atom that can share an electron with them. They will not react together.

Answer 4

Lots of solutions.

Answer 5

You should do your own homework lol, im guessing you meant bromine