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Calculate the mass of iodine produced when 2.85 g of chlorine gas is bubbled through an excess amount of potassium iodide solution.

Cl2(g) + KI(aq) ==> I2(s) + KCl(aq)

2006-11-28 17:05:41 · 2 answers · asked by Legend 4 in Science & Mathematics ➔ Chemistry

2 answers

mol of Cl2
=2.85/71
=0.0401 mol

mol ratio of Cl2 : I2
=1 : 1

mass of I2
=0.0401*254
=10.1854g

2006-11-28 17:10:45 · answer #1 · answered by pigley 4 · 0⤊ 0⤋

1 mole of Cl2 = 71 g of Cl2 produce 254 g of I2
So 2.85 g of Cl2 produce 254*2.85/71 = 10.195 g of I2

2006-11-29 01:39:52 · answer #2 · answered by chemboy_bkk 1 · 0⤊ 0⤋