a=2 and r=3
2006-11-28 15:13:00 · 4 answers · asked by Mz. Araseli 2 in Science & Mathematics ➔ Mathematics
term n = 2*3^n-1
So term 1=2*3^0 = 2
term 5 = 2*3^4 = 162
2006-11-28 15:30:45 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
right here we've, a = fifty 4, r = a million/3 Tn = fifty 4(a million/3)^(n -a million) = 2 OR. . (a million/3)^(n -a million) = 2/fifty 4 = a million/27 (a million/3)^(n -a million) = (a million/3)^3 therefore n -a million = 3 n = 4 Sn = fifty 4(a million -(a million/3)^4) / (a million -a million/3) Sn = fifty 4(80/80 one) / 2/3 Sn = 80 A n s w e r
2016-11-29 22:08:47 · answer #2 · answered by ? 4 · 0⤊ 0⤋
5th term = 162
nth term = a x r "(n-1) ...... (to be read as "a multiplied by r to the power of (n-1))
2006-11-28 15:16:47 · answer #3 · answered by Srinivas c 2 · 0⤊ 0⤋
t5=ar^4
=2(3)^4
=162
2006-11-28 15:14:50 · answer #4 · answered by raj 7 · 0⤊ 0⤋