"Charles Law", I understand the formula and equation, just a little confused on this one.
Hydrogen gas was cooled from 150* C to 50* C. Its new volume is 75 mL. What was its original volume? PLEAse help.
2006-11-28 14:22:12 · 2 answers · asked by B-Rad 4 in Science & Mathematics ➔ Chemistry
Charles Law is V1/T1 = V2/T2. You know V1 (75 mL), T1 (50C) and T2 (150 C). However, don't forget that, in all thermodynamic laws, scalar temperatures are always stated as Kelvins so,
T1 = 50 + 273 = 323 K and T2 = 150 + 273 = 423 K.
So, 75 mL/323 K = V2/423 K. Solving for V2, you get
V2 = (75 mL x 423 K)/323 K, so V2 = 98 mL.
One thing I always do is to think about the answer. Hotter gases take more room than cooler gases at the same pressure so this answer makes sense.
2006-11-28 17:36:49 · answer #1 · answered by Luha 3 · 0⤊ 0⤋
Volume is directly proportional to temperature. So the original volume would've been 225 mL.
2006-11-28 14:28:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋